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We will investigate the vector function r(t) = tcos(t) i + tsin(t) j +e^t k
Now define some options for our plots
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Let's see what the curve r looks like
To take a derivative in Maple, use the diff(...)function. Specify the expression and the variable - diff(expression, variable)
The derivative of r is the velocity vector, v:
And the second derivative of r (the derivative of v) is the acceleration vector:
We can compute the Unit Tangent Vector T
And we can easily compute the Unit Normal Vector
![(([-2*sin(t)-t*cos(t), 2*cos(t)-t*sin(t), 0])/(1+cos(t)^2+t^2*sin(t)^2+sin(t)^2+t^2*cos(t)^2)^(1/2)-1/2*([cos(t)-t*sin(t), sin(t)+t*cos(t), 1])*(2*t*sin(t)^2+2*t*cos(t)^2)/(1+cos(t)^2+t^2*sin(t)^2+sin...](images/TangentAndNormalVectors_41.gif)
![(([-2*sin(t)-t*cos(t), 2*cos(t)-t*sin(t), 0])/(1+cos(t)^2+t^2*sin(t)^2+sin(t)^2+t^2*cos(t)^2)^(1/2)-1/2*([cos(t)-t*sin(t), sin(t)+t*cos(t), 1])*(2*t*sin(t)^2+2*t*cos(t)^2)/(1+cos(t)^2+t^2*sin(t)^2+sin...](images/TangentAndNormalVectors_42.gif)
![(([-2*sin(t)-t*cos(t), 2*cos(t)-t*sin(t), 0])/(1+cos(t)^2+t^2*sin(t)^2+sin(t)^2+t^2*cos(t)^2)^(1/2)-1/2*([cos(t)-t*sin(t), sin(t)+t*cos(t), 1])*(2*t*sin(t)^2+2*t*cos(t)^2)/(1+cos(t)^2+t^2*sin(t)^2+sin...](images/TangentAndNormalVectors_43.gif)
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![(([-4*sin(t)-2*t*cos(t), 4*cos(t)-2*t*sin(t), 0])+([-2*sin(t)-t*cos(t), 2*cos(t)-t*sin(t), 0])*t^2-([cos(t)-t*sin(t), sin(t)+t*cos(t), 1])*t)/((2+t^2)^(3/2)*((5*t^2+8+t^4)/(2+t^2)^2)^(1/2))](images/TangentAndNormalVectors_48.gif)
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Wasn't that easy?
Let's try another...First reset our variables
In the following, don't type the letter e for e^t. Use the expression box on the left to pick out e^a or use exp(t)
![1/2*(([2*exp(t)*cos(t), -2*exp(t)*sin(t), exp(t)])/(2*(exp(t))^2*sin(t)^2+2*(exp(t))^2*cos(t)^2+(exp(t))^2)^(1/2)-1/2*([exp(t)*sin(t)+exp(t)*cos(t), exp(t)*cos(t)-exp(t)*sin(t), exp(t)])*(4*(exp(t))^2...](images/TangentAndNormalVectors_69.gif)
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Beats doing it by hand!